Calculate the molar heat of combustion of anthracene

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SUMMARY

The discussion focuses on calculating the molar heat of combustion of anthracene (C14H10) using a calorimetry experiment. A 2.56g sample of anthracene was burned in a calorimeter with a mass of 945g, containing 1.50L of water. The initial temperature was 20.5°C, and the final temperature reached 34.3°C. The calculations involved using the equations n=m/M and Q=mcΔt, with a final emphasis on presenting the answer to three significant figures and converting the result from kJ/mol to J/mol.

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  • Understanding of calorimetry principles
  • Knowledge of the equations n=m/M and Q=mcΔt
  • Familiarity with significant figures in scientific calculations
  • Ability to convert energy units from kJ to J
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Specter

Homework Statement


A 2.56g sample of anthracene, C14H10, was burned to heat an aluminum calorimeter (mass=945 g). The calorimeter contained 1.50 L of water with an initial temperature of 20.5 C and a final temperature of 34.3 C.

a) Calculate the molar heat of combustion of anthracene.

Homework Equations


n=m/M
Q=mcΔt

The Attempt at a Solution



My work:

https://i.imgur.com/WYNiBRD.png

WYNiBRD.png


https://i.imgur.com/LNjq3CG.png

LNjq3CG.png


Did I do the steps correctly? Did I include the correct sig figs? How would I convert my final answer to J/mol instead of kJ/mol? Thanks! If you need me to type out the work instead of using pictures I can!
 

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Your procedure looks correct (I haven't checked the arithmetic). Your given data are all to 3 sig figs, so your answer should be given to 3 sig figs. (You were right to use more sig figs in the intermediate calculations, but your final answer should be to 3 s.f.)
After getting so much right, you can't convert kJ to J?
PS Thanks for offering to type it out; many people don't and post illegible scribble, but your pictures are very clear and legible.
 
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Specter said:
If you need me to type out the work instead of using pictures I can!

That's preferable (check the forum rules) - not only it usually makes things easier to follow, it also makes it possible to quote the solution and mark places were something is wrong.
 
mjc123 said:
Your procedure looks correct (I haven't checked the arithmetic). Your given data are all to 3 sig figs, so your answer should be given to 3 sig figs. (You were right to use more sig figs in the intermediate calculations, but your final answer should be to 3 s.f.)
After getting so much right, you can't convert kJ to J?
PS Thanks for offering to type it out; many people don't and post illegible scribble, but your pictures are very clear and legible.
Thanks! I ended up figuring out how to convert kJ to J... It was very easy :biggrin:
 

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