So how do you solve for v2?Finding Velocity After Acceleration?

[SoConfused__]

Homework Statement

If Carol Ann wakes up and crawls across her bedroom at an aceeleration of 0.45 m/s^2 forward for 1.3s, how fast would she be going after 1.3 seconds if he had started with a velocity of 0.25 m/s forward?

Homework Equations

d = (v1+v2/2)t
a = v2 - v1 /t

The Attempt at a Solution

so we're looking for V right? Which would be v1 & v2.
v2 - v1 = at
= 0.25 x 1.3
= 0.325

but the answer here says 0.84 m/s forward.

What am I doing wrong? Please help, thank you so much.

 

[willem2]

The equation you use is right. How you apply it, is not. I don't understand at all what you meant with" we're looking for V right? Which would be v1 & v2.
v1 is the initial velocity, which is 0.25 m/s
v2 is the final velocity, which is what were after.
you haven't used the acceleration at all.

 

[SoConfused__]

But what we're looking for is "how fast would she be going after the 1.3 s" isn't that the speed?

 

[Redbelly98]

Homework Statement

If Carol Ann wakes up and crawls across her bedroom at an aceeleration of 0.45 m/s^2 forward for 1.3s, how fast would she be going after 1.3 seconds if he had started with a velocity of 0.25 m/s forward?

Homework Equations

d = (v1+v2/2)t
a = v2 - v1 /t

The Attempt at a Solution

so we're looking for V right? Which would be v1 & v2.
v2 - v1 = at
= 0.25 x 1.3
= 0.325

but the answer here says 0.84 m/s forward.

What am I doing wrong? Please help, thank you so much.

But what we're looking for is "how fast would she be going after the 1.3 s" isn't that the speed?

It is the velocity after the 1.3 s have elapsed, which is v2 in the equation you used. And v1 is the velocity at the beginning of the 1.3 s -- and they tell you what it is in the problem statement. They also tell you what the values of a and t are.

To summarize:

v2 - v1 = a t, as you said.

You are trying to find v2. You are told what everything else in the equation is.