SO(n) actions on vector bundles

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Discussion Overview

The discussion centers on the action of the special orthogonal group SO(n) on the tangent bundle of oriented Riemannian n-manifolds and oriented vector bundles with Riemannian metrics over smooth manifolds. Participants explore whether such actions can be defined independently of a chosen basis.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants assert that there is generally no natural action of SO(n) on the tangent bundle of an oriented Riemannian n-manifold, as it cannot be defined independently of a basis.
  • Others note that SO(n) does act on the frame bundle, which can be viewed as a lift of the tangent bundle to a principal bundle.
  • It is mentioned that the 2-dimensional case is unique, as the frame bundle of an oriented 2-manifold is a circle, allowing for a fixed angle to determine an orthonormal frame.
  • One participant elaborates that if a unit vector is extended to an oriented n-frame, the action of SO(n) on this frame depends on the choice of the orthogonal complement to the vector.
  • Another participant agrees, stating that unless the action fixes the vector or the vector itself determines a basis, the specific tangent vector to which the action is applied must be specified.

Areas of Agreement / Disagreement

Participants generally disagree on the existence of a natural action of SO(n) on the tangent bundle, with multiple competing views regarding the conditions under which such actions can be defined.

Contextual Notes

The discussion highlights limitations related to the dependence on basis choices and the specific conditions required for defining actions of SO(n) on tangent bundles.

wofsy
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An oriented surface with a Riemannian metric has a natural action of the unit circle on its tangent bundle. Rotate the tangent vector through the angle theta in the positively direction.

Is there a natural action of SO(n) on the tangent bundle of an oriented Riemannian n-manifold?

Same question for any oriented vector bundle with Riemannian metric over a smooth manifold.
 
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In general, the answer is no. I don't see how one could define it independent of basis.

It does act, however, on the frame bundle (kind of like a lift of the tangent bundle to a principal bundle). The 2-dimensional case is quite special, since the frame bundle of an oriented 2-manifold is a circle (i.e. fix an angle - then orientation gives you an orthonormal frame).
 
zhentil said:
In general, the answer is no. I don't see how one could define it independent of basis.

It does act, however, on the frame bundle (kind of like a lift of the tangent bundle to a principal bundle). The 2-dimensional case is quite special, since the frame bundle of an oriented 2-manifold is a circle (i.e. fix an angle - then orientation gives you an orthonormal frame).

Right - so what you are saying implies the following. take a unit vector and extend it to an oriented n-frame arbitrarily, keeping the vector as the first element of the frame. Let SO(n) act on this frame. Then the image of v under this action depends on the choice of the orthogonal complement to v.
 
Yes, I believe that's precisely it. Unless the action fixes v (or v itself determines a basis, as in the 2-dimensional oriented case), you have to specify which tangent vector to send it to.
 

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