Soccer - What was the impulse on the soccer ball

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To calculate the impulse delivered to the soccer ball, the direction of the velocities must be considered. The initial velocity of the ball is 18 m/s to the north, while the final velocity after being struck is 24 m/s to the south, which is treated as negative. Using the impulse formula, the calculation involves subtracting the initial momentum from the final momentum, resulting in an impulse of -42 kg·m/s. Understanding the sign convention for direction is crucial in solving this problem correctly. The discussion emphasizes the importance of consistently applying direction in momentum calculations.
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Homework Statement


A 0.40 kg soccer ball approaches a player
horizontally with a velocity of 18 m/s to the
north. The player strikes the ball and causes
it to move in the opposite direction with a
velocity of 24 m/s.
What impulse was delivered to the ball by
the player? Answer in units of kg · m/s.

2. Homework Equations
M(v)f-M(v)i=impulse

The Attempt at a Solution


i did (.4kg)(24m/s)-(.4kg)(18m/s) and i got it wrong so if u can please help
 
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gansta344u said:

Homework Statement


A 0.40 kg soccer ball approaches a player
horizontally with a velocity of 18 m/s to the
north. The player strikes the ball and causes
it to move in the opposite direction with a
velocity of 24 m/s.
What impulse was delivered to the ball by
the player? Answer in units of kg · m/s.

2. Homework Equations
M(v)f-M(v)i=impulse

The Attempt at a Solution


i did (.4kg)(24m/s)-(.4kg)(18m/s) and i got it wrong so if u can please help


The key here is direction.

If it comes in at 18m/s and reverses then it returns at -24m/s.

-24 - 18 = -42
 


The key to this is directions. Choose one and then all velocities are either positive or negative relative to that. Does that help?

The Bob

P.S. It's not my night; second after post, apologies once again.
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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