Solenoid Magnetic Field wire spacing Help

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SUMMARY

The discussion focuses on calculating the magnetic field strength inside a solenoid using 12 meters of 0.50mm diameter copper wire and a power supply capable of 17A. The magnetic field strength formula B = μ₀nI is applied, where n represents the number of turns per unit length. The user initially calculates 173.6 turns but questions the accuracy of this number due to the wire's diameter affecting the spacing. A corrected magnetic field strength of 0.00408T is suggested, indicating the importance of precise calculations in determining solenoid properties.

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  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the formula B = μ₀nI
  • Knowledge of wire diameter and its impact on coil density
  • Basic skills in geometry for calculating circumference and area
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Homework Statement


You have 12m of 0.50mm diameter copper wire and a power supply capable of passing 17A through the wire.
What magnetic field strength would you obtain inside a 2.0cm diameter solenoid with the wire spaced as closely as possible?

Homework Equations


B=u0nI

The Attempt at a Solution


I found the number of loops by
D=.002+2*1*10-3m (diametre plus 2 radi of wire)?
then n=12/circumfrence =173.6turns (C=pi*D
then I subbed all the values and got 0.0037T which is wrong
all help appreciated - I think my problem is in calculating the number of turns??
 
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The diameter of the wire will effect the pitch (loop density) of the coil, but not the total number of loops. I take it you have the answer to the problem?
 
Last edited:
Hey, its for an online mastering physics test - - - - using D as .02m I get .00408T but I didnt use the radius at all so I think it may be wrong?
 

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