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Solid ball dropped on ground again

  1. Mar 28, 2009 #1
    1. The problem statement, all variables and given/known data
    I got struck with this problem again in the review questions and still can't do it, I think this problem shows a major gap in my knowledge of the subject.

    A solid ball of radius R is set spinning with angular speed [tex]\omega[/tex] about a horizontal axis. The ball is then lowered vertically with negligible speed until it just touches a horizontal surface and is released. If the coefficient of kinetic friction between the ball and the surface is [tex]\mu[/tex], find the linear speed of the ball once it achieves pure rolling motion and the distance it travels before its motion is pure rolling.


    2. Relevant equations
    [tex]W=\Delta K[/tex]

    [tex]I_0\omega_0=I\omega[/tex]

    [tex]I=\frac{2}{5}MR^2[/tex]

    [tex]v=R\omega[/tex]

    3. The attempt at a solution
    Now i dont think i can use conservation of angular momentum because the external force of friction is acting on the ball, which brings me to another question...how can one use conservation of mechanical energy for a ball rolling down an incline? ie mgh=1/2 mv^2 + 1/2I[itex]\omega ^2[/itex]

    To solve this problem i would probably say
    [tex]-\frac{1}{2}I\omega^2+\frac{1}{2}I\omega_f ^2 + \frac{1}{2}MR^2\omega_f ^2=F_fs[/tex]
    but i dont think i can use [tex]F_f = \mu Mg[/tex]
    and i am not given how far the ball slips before its in pure rolling motion (actually its asked int he question to find that) so i dont think i have enough information to solve this problem.
     
  2. jcsd
  3. Mar 29, 2009 #2
    Forget energy conservation. Just fall into momentum conservation.

    The torque about the point of the ball which touches the gorund at a given instant is zero. So you can apply momentum conservation. For the case initial momentum is just due to the rolling but the final momentum is rolling plus translational. And in the final momentum term do not forget to replace v by wr.
     
  4. Mar 29, 2009 #3
    i am a bit confused
    in this problem
    https://www.physicsforums.com/showthread.php?t=301129
    we had a cylinder rolling down a hill and it had friction working on it
    other times we dont seem to pop in friction to the equations
    whats the deal with that?
     
  5. Mar 29, 2009 #4
    Friction is inevitable. It always acts.

    But the torque bu the friction about the point of contact is

    Torque=(Friction)(Distance)

    The distance is zero
    Hence torque is zero
     
  6. Mar 29, 2009 #5

    Doc Al

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    Staff: Mentor

    Certainly the angular momentum about the center of mass is not conserved, but you can apply conservation of angular momentum about a fixed point on the surface. In that case the torque due the external force is zero.

    In that kind of problem the friction is static friction and does no work. So energy is conserved.

    The problem with this is that the ball both rolls and slips, so defining "s" is tricky. (It's not just the displacement of the ball's center.)
    Why not?
    Either use conservation of angular momentum or basic dynamics/kinematics. There's a force on the ball: Apply Newton's 2nd law for rotation and translation, then solve for the point where the condition for rolling without slipping is met.
     
  7. Mar 30, 2009 #6
    doc al, you have enlightened me somewhat but i have been thinking about your post for about 20 mins now and not sure about "conservation of angular momentum about a fixed point on the surface" and also the last bit about applying newtons 2nd law for rotation and translation.
    i tried to write a single equation down but nothing springs to mind

    if the question said static friction instead of kinetic friction would the conservation of energy equation i used apply?
     
  8. Mar 30, 2009 #7

    Doc Al

    User Avatar

    Staff: Mentor

    If you take some point along the surface as your origin, then angular momentum about that point will be conserved. (The friction force exerts no torque about that point, since its line of action will pass through that origin.) But you don't need to use this method, if it's not clear to you.

    You need two equations: One for rotation; one for translation. Just apply Newton's 2nd law to find the accelerations. Then use a bit of kinematics. The center of the ball speeds up from v = 0 to some final speed vf, while the angular speed slows down from the initial ω to some final angular speed ωf. The final translational and rotational speeds must satisfy the condition for rolling without slipping. (Hint: Solve for the time it takes to reach that final speed.)

    If the friction were static, no work would be done and energy would be conserved.
     
  9. Apr 2, 2009 #8
    thanks for the help doc al, greatly appreciated
    i will have to do some thinking about this one and a bit of reviewing
     
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