Solution Of A Differential Equation]

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The discussion revolves around solving the second-order differential equation d²y/dx² = c/x, where c is an arbitrary constant. The original poster speculated that the solution might be a trigonometric equation, but responses clarified that this assumption is incorrect. Instead, the hint provided suggests using the relationship between the first and second derivatives, indicating that if v = dy/dx, then the equation simplifies to dv/dx = c/x. Further exploration is needed to find v(x), which will lead to the solution of the original equation. The conversation highlights the importance of correctly interpreting the form of the differential equation for effective problem-solving.
NEWO
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Hi all I was wondering if i could get some help with this.

1. I need to be able to solve a second order differential equation,

2. d^2(y)/dx^2= c/x

where c is an arbitary constant.

I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

Thanks for your time

N



The Attempt at a Solution

 
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NEWO said:

The Attempt at a Solution

You left this part of the template blank. What work have you done on the problem?
 
Well it's quite easy, here's a hint: succesive 'something' will do the trick.
 
WHY would you tnink "that the solution would take form of a trigonometrial eqauation"?
 
NEWO said:
I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

Hi NEWO! :smile:

Noo … you're thinking of d²y/dx² = -cy.

Hint: just say the equation in ordinary English:

"y is a function of x, and if you differentiate it twice, you get c/x." :smile:
 
If you let v= dy/dx then d^2y/dx^2= dv/dx so your equation becomes dv/dx= c/x. What is v(x)?
 
Halls, isn't your hint really the solution?
 
Well, almost. There is still a tiny amount of work to be done. And I suspect that "NEWO" won't bother to come back to look at the responses.
 

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