Solution of Schrodinger equation for free electron

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SUMMARY

The discussion centers on the solutions of the Schrödinger equation for free electrons versus confined electrons. For confined electrons, the solution is represented as ψ=A*exp(jKx) + B*exp(-jkx), indicating two independent wave functions due to the presence of a confining potential. In contrast, free electrons have solutions of the form ψ = A*exp(jkx) or ψ = B*exp(-jkx), reflecting their unidirectional motion without confinement. The necessity of two solutions arises from the second-order nature of the Schrödinger equation, which requires proper boundary conditions to determine the valid quantum states.

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  • Understanding of Quantum Mechanics principles
  • Familiarity with the Schrödinger equation
  • Knowledge of wave functions and their representations
  • Basic concepts of boundary conditions in differential equations
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  • Study the implications of boundary conditions on quantum states
  • Explore the properties of second-order ordinary differential equations (ODEs)
  • Learn about the Hamiltonian operator in quantum mechanics
  • Investigate the concept of self-adjoint operators in quantum theory
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Hi, i am beginning elementary Quantum Mechanics as my course. While studying one question arise in my mind :

In the solution of Schrödinger wave equation there are two parts.

ψ=A*exp(jKx) + B*exp(-jkx). (for confined electron)

But when dealing with free electron the solution is of the following pattern :

ψ = A*exp(jkx) or ψ = B*exp(-jkx).

Can anyone tell me the reason behind that?
 
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the power of the exponential describes the direction of the evolution.
here what you have is a solution that either describes a particle traveling in the positive or negative x direction. This is fine, because there is no confining potential, so the solution only travels one way through space. In the previous solution the particle is in some potential, so its motion must be considered in both dircetions.
 
There are ALWAYS 2 linearly independent solutions to the Schrödinger equation, because it's a second order ODE. Which one "survives" and describes quantum states is a matter of rightfully implementing boundary/limit conditions which are necessary to make the hamiltonian or the momentum operator (essentially) self-adjoint.
 
Thank you raymo and dextercioby.
 

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