Solve 1D Motion Questions: Determine Velocity, Max Height, Time Req.

[oreosama]

Homework Statement

a rock is thrown nearly vertical upward from the edge of a tall building of height H. it just misses the edge of the building on the way down and strikes the ground T seconds after being thrown. given H, T

determine the initial velocity of the rock
the max height it reaches above its starting point
the time to reach its max height

Homework Equations

v= v_0 + at

x = x_0 + v_0*t + 1/2*a*t^2

v^2 = v_0^2 + 2a(x - x_0)

The Attempt at a Solution

x_0 = H
x = 0
v_0 = ?
v = ?
a = g
t = T

with these as inputs I don't see how I can manipulate algebra to get the things I want. this is a recurring theme with the rest of my homework it seems:

a flowerpot falls off a windowsill and falls past a window below. a person inside the building notices that it takes T seconds to go from the top to the bottom of the window. the window is h meters high. given h, T

determine how far above the window is the windowsill.

v= v_0 + at

x = x_0 + v_0*t + 1/2*a*t^2

v^2 = v_0^2 + 2a(x - x_0)x_0 = 0
x = q + h (figuring out q is the goal)
v_0 = 0
v = v
a = g
t = Tone again i feel like when i mess with the algebra i end up going in circles where I can't get everything solved within means of the terms given... hurts my head. i think I am doing something fundamentally wrong, let me know.

 

[azizlwl]

1. x_0 = H
x = 0
v_0 = ?
v = ?
a = g
t = T
...
x=H
x_0=0

2. x=u²/2a

h=ut+0.5at²

 

[voko]

With v_0, the object can reach the maximum height h (relative to the top of the building). That gives you an equation relating v_0 and h. It takes T_u to lose the initial speed v_0 going upward to the maximum height. That gives you an equation relating v_0 and T_u. It takes T_d to fall from H + h to the ground. That gives you an equation relating H, T_d and h. And T_u + T_d = T. So you have four equations and four unknowns v_0, h, T_u and T_d, which you can solve.