Dragonfall
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There are 2n red and 2n blue points on a plane. I have to show that there's a line bisecting them. No idea how. Not homework.
The discussion revolves around the problem of finding a line that bisects 2n red and 2n blue points on a plane, ensuring that n points of each color lie on either side of the line. The conversation explores various approaches to this problem, including combinatorial and analytical methods, while addressing specific conditions such as the arrangement of points.
Participants express differing views on the methods to prove the existence of such a bisecting line, with some advocating for combinatorial approaches while others explore analytical methods. There is no consensus on the best approach or the implications of the conditions set forth.
Participants discuss the implications of the condition that no three points of the same color lie on a line, and the potential limitations of the proposed methods, particularly regarding the continuity of the functions involved.
Individuals interested in combinatorial geometry, mathematical proofs, or those exploring methods for separating points in geometric configurations may find this discussion relevant.
slider142 said:First show that there exists a line on which none of the points lie. Then create 2 functions, one tells you how many dots are left of the line as a function of the angle t that the line makes with the positive x-axis and the other how many are right of it, where the pivot point is not in the smallest circle containing the points. Show that the function that is the difference of these functions must be 0 for some t. This part may be difficult, or there may be a better approach. The fixed point method above works great for continuous functions, but these functions are not.
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