The discussion revolves around calculating the number of possible 6-digit codes Jacob can create for his bank account using the digits 0 to 9, with specific conditions that the first digit must be odd and the last digit must be even, and that no digits can be repeated.
Participants generally agree on the approach of selecting the first and last digits first, but there are variations in the proposed calculations and the exact number of choices for the remaining digits, indicating some uncertainty in the final answer.
There are unresolved aspects regarding the exact calculation method and the implications of the choices made for the remaining digits after the first and last have been selected.
greprep said:"Jacob needs to create a 6-digit code for his bank account using the digits from 0 to 9. He wants the first digit to be odd and the last digit to be even. If he does not repeat any digits, how many different 6-digit codes could Jacob create?"
Would the best way to solve this be: (5)(9)(8)(7)(6)(4)?
greprep said:Oh, I see. So I would put in 5 first for the potential odd number (1,3,5,7,9), then 5 at the end for the potential even numbers (0,2,4,6,8), and that leaves us with 10-2 (8) choices for the second, 7 for the third, 6 for the 4th, etc?