Solve a Simple Physics Problem for High School: Pelican and Falling Fish"

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SUMMARY

The discussion focuses on solving a physics problem involving a fish dropped from a rising pelican. The initial velocity of the pelican is 0.41 m/s, and the acceleration due to gravity is 9.8 m/s². For part (a), the final velocity of the fish after 1.8 seconds is calculated using the formula vf = vi + at, resulting in a velocity of 17.61 m/s downward. For part (b), the distance below the pelican after 1.8 seconds is determined using the formula s = vit + 1/2at², yielding a distance of 15.87 meters.

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playa007
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i have just started physics in high school and i got this problem i want some help on this question:

A small fish is dropped by a pelican that is rising steadily at 0.41m/s.
a)After 1.8s, what is the velocity of the fish? Answer in units of m/s
b)How far below the pelican is the fish after the 1.8s? Answer in units of m.

if anyone can show me the steps and formulae, thanks.
 
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what steps have you taken so far? most people on this board like to see that you put some work in a problem before submitting it for help. Here is a hint:

What effect does the fact that the pelican is rising have on the fall of the fish? Is gravity affected when you are moving against gravity at a gentle constant velocity?

~Lyuokdea
 
vi= 0.41 m/s
t-1.8s
vf= ?
a=9.8 m/s
therefore u use vf=vi+at
that is what i think i not quite sure for part a.
for part b u use s=(vi+vf/2)*t or s=vit+1/2at^2
 

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