Finding Pelican's Initial Speed and Distance Traveled by Fish - Can You Help Me?

  • Thread starter Mitxigan
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  • #1
Mitxigan
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A pelican flying along a horizontal path drops
a fish from a height of 4.9 m. The fish travels
7.5 m horizontally before it hits the water
below.
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s^2
Answer in units of m/sIf the pelican was traveling at the same speed
but was only 3.0 m above the water, how
far would the fish travel horizontally before
hitting the water below?
Answer in units of mCan someone help me i have no idea how to solve this I am lost.
 
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  • #2
Sure. You did well on nuber one of the template. Now help us to provide adequate assistance (at the right level) by also completing 2 and 3. PF rules don't allow us to help if you don't . Why ? See the guidelines !

1. Homework Statement

Homework Equations


3. The Attempt at a Solution
[/B]
And eh, welcome to PF !
 
  • #3
BvU said:
Sure. You did well on nuber one of the template. Now help us to provide adequate assistance (at the right level) by also completing 2 and 3. PF rules don't allow us to help if you don't . Why ? See the guidelines !

1. Homework Statement

Homework Equations


3. The Attempt at a Solution
[/B]
And eh, welcome to PF !

ok number 2 is

vx
dx 7.5
t

vfY
voY 0
aY -9.8
dY -4.9
t

i used this equation

s=1/2gt^2

but i can get the right answers

and number 3 is

i used that equation but i can´t get the right answerand sorry I am new idk how to ask correctly here and stuff
 
  • #4
s=1/2gt^2
When you use this equation, what is the result telling you?
 
  • #5
2. ) s=1/2gt^2
What is s ?
 
  • #6
BvU said:
What is s ?
s is speed
 
  • #7
BvU said:
What is s ?

like i get the wrong answer all the time
 
  • #8
Like you multiply m/s^2 with s^2 and you are surprised you don't get something with the dimension of m/s ?
 
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  • #9
Mitxigan said:
s is speed
No, in the standard SUVAT equations s is distance. Speeds, initial and final, are represented by u and v.
 
  • #10
BvU said:
Like you multiply m/s^2 with s^2 and you are surprised you don't get something with the dimension of m/s ?
No is just that i get the answer wrong not the dimensions
 
  • #11
So now apply the equation I quoted, and describe what it can tell you. (Remember, s is not speed.)
 
  • #12
NascentOxygen said:
So now apply the equation I quoted, and describe what it can tell you. (Remember, s is not speed.)
haruspex said:
No, in the standard SUVAT equations s is distance. Speeds, initial and final, are represented by u and v.

I used the equation Vx=deltaX/t

And i got it right thanks tho ;)
 
  • #13
Mitxigan said:
I used the equation Vx=deltaX/t

And i got it right thanks tho ;)
That's the only equation you used? Since you showed no working here, we'll have to accept your word that you solved it correctly.
 
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