Solve Algebra Word Problem: Bobbie Has $1.54 in Coins

[daigo]

Bobbie has $1.54 in quarters, dimes, nickels, and pennies. He has twice as many dimes as quarters and three times as many dimes as nickels. The number of pennies is the same as the number of dimes. How many of each coin does he have?

Okay, so this is what I have:

Total:
0.25q + 0.10d + 0.05n + 0.01p = 1.54

What I got from the word problem:
p = d
.25q * 2 = d
.05n * 3 = d

Simplified:
p = d
.50q = d
.15n = d

So this would mean:
.50q = .15n
Because both variable 'd' are the same value

So:

q = d / .50
n = d / .15

I can't seem to plug in anything for anything because I keep ending up with two or more variables in a single linear equation. How would I go about doing this?

 

[tiny-tim]

hi daigo!

What I got from the word problem:
p = d
.25q * 2 = d
.05n * 3 = d

no, q and n are numbers of coins, not values

 

[daigo]

Oh, thanks. I got it now. How embarassing...