Solve Basic Vector Problem: Hawk Speed & Shadow Speed in m/s

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SUMMARY

The discussion focuses on calculating the speed of a hawk's shadow on the ground when the hawk dives at a speed of 4.24 m/s at an angle of 61.7 degrees below the horizontal. The correct method involves using the formula A_x = A cos(θ) to find the x component of the velocity vector. The user calculated 2.01013 m/s but received an incorrect response from their homework program, indicating a potential misunderstanding or misapplication of the angle's sign in the cosine function. Engaging with a professor for clarification is recommended.

PREREQUISITES
  • Understanding of vector components and trigonometric functions
  • Familiarity with the cosine function and its application in physics
  • Basic knowledge of projectile motion
  • Experience with homework programs like Quest
NEXT STEPS
  • Review vector decomposition in physics
  • Learn about the correct use of angles in trigonometric calculations
  • Explore the concept of shadow projection in relation to motion
  • Consult resources on common pitfalls in physics homework problems
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Students studying physics, particularly those tackling vector problems, and anyone seeking to understand the relationship between motion and shadow projection.

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Homework Statement



When the Sun is directly overhead, a hawk dives toward the ground at a speed of 4.24 m/s

If the direction of his motion is at an angle of 61.7 below the horizontal, calculate the speed of his shadow along the ground

Answer in units of m/s

Homework Equations



A_x = A cos\theta


The Attempt at a Solution



I will want to find the x component of the velocity vector.

4.24 Cos (-61.7) = 2.01013

I put this answer into my homework program (Quest) and it was wrong. What am I missing here?
 
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Welcome to PF, Ollie. Your calc seems correct to me.
Sounds like a good opportunity to visit your prof.
 

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