Solve Centripetal Force Question: Find Vehicle Speed

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SUMMARY

The discussion revolves around calculating the speed of a vehicle moving over a hill with a radius of 18 meters, where the driver experiences minimal contact with the seat. The key equations utilized include Newton's second law and the centripetal force formula, specifically (mv²)/r = mg, leading to the derived speed formula v = (rg)^(0.5). The normal force (N) is zero at the top of the hill, indicating a state of weightlessness for the driver, which is clarified through the use of a free body diagram (FBD).

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  • Understanding of Newton's second law of motion
  • Familiarity with centripetal force concepts
  • Ability to interpret free body diagrams (FBD)
  • Basic knowledge of gravitational force (g)
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  • Study the derivation of centripetal force equations in detail
  • Learn how to draw and analyze free body diagrams (FBD)
  • Explore scenarios involving weightlessness in different contexts
  • Investigate the effects of varying radius on vehicle speed over hills
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Students studying physics, particularly those focusing on mechanics and centripetal motion, as well as educators looking for practical examples of these concepts in action.

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Homework Statement


An automobile moves at constant speed over a hill with a radius of 18 m. At the top of the hill, the drivers notices that she barely remains in contact with the seat. find the speed of the vehicle.


Homework Equations


Using Newton's second lay, and centripetal force formula

The Attempt at a Solution



N=0
W-N = Fc <centripetal force>

therefoce, (mv^2)/r = mg

and v= (rg)^0.5

I do not have the answer, so wondering if I have made any mistake somewhere above ?
 
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looks okay to me.
 
i don't quite get it

"N=0"

what does N rep?
and where did you get the equation "W-N = Fc <centripetal force>"
isn't the formula for centripetal force, (mv^2)/r?
and how do know if that equals mg?

ugh. this stuff is pretty new to me and it's confusing me. :'(
 
N represents normal reaction. Draw a free body diagram of normal reaction and weight. The centripetal force is the resultant force of weight and normal reaction.
 
oooooooooooh, i get it.- so FBD is the answer!

but why is Fn zero again? is it because she "barely remains in contact with the seat"? then, it's not the same as when a person feels weightless, is it?
in what other situations is like this?
 
thanks a lot to all!

and, as for how did i get there<assuming that me's right>
centripetal force is the resultant, and
there must be something that provides it...
in this case,
the car is pushed up by the road, down by the gravity
and the net force is keeping the car in the circle
as normal force is against or negative..
so...
I think drawing free body diagram would help
 
a seeker said:
oooooooooooh, i get it.- so FBD is the answer!

but why is Fn zero again? is it because she "barely remains in contact with the seat"? then, it's not the same as when a person feels weightless, is it?
in what other situations is like this?

yea, because she is not being pushed by her seat so shez weightless..
other situation..a free falling elevator, with some thing in it, and that thing would be weightless
 
k. thnx a lot. i think i kinda understand it now...
 

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