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look416

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## Homework Statement

The diagram shows a semicircle APB on AB as diameter. The midpoint of AB is O. The point P on the semicircle is such that the area of the sector POB is equal to twice the area of the shade segment. Given that angle POB is [tex]\theta[/tex] radians, show that

3[tex]\theta[/tex] = 2([tex]\pi[/tex]-sin[tex]\theta[/tex])

## Homework Equations

## The Attempt at a Solution

using formula

Area of circle = [tex]\frac{1}{2}[/tex]r

^{2}[tex]\theta[/tex]

and

Area of segment = [tex]\frac{1}{2}[/tex]r

^{2}([tex]\theta[/tex] - sin [tex]\theta[/tex] )

heres the problems

from the picture http://img130.imageshack.us/img130/1790/001tz.jpg

questions 4

the the angle of the segment is [tex]\pi[/tex]-[tex]\theta[/tex]

there I am clueless even i inserted the info i have

what i really get is

[tex]\theta[/tex]=2[[tex]\pi[/tex]-[tex]\theta[/tex]-sin([tex]\pi[/tex]-[tex]\theta[/tex])]

of course we can't use formula blindly so anyone can help me there
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