Solve Difficult Problem: Average Density of Rectangular Parallelopiped

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SUMMARY

The discussion focuses on calculating the average density of a rectangular parallelopiped with dimensions 28.0 cm x 19.1 cm x 2.000 m, which floats in water with 3.17 cm above the surface. The problem involves applying principles of buoyancy and density to determine the average density of the object. Participants emphasize the importance of understanding the relationship between the volume submerged and the buoyant force, referencing Archimedes' principle as a key concept in solving the problem.

PREREQUISITES
  • Understanding of buoyancy and Archimedes' principle
  • Knowledge of density calculations
  • Familiarity with volume calculations for rectangular solids
  • Basic geometry related to three-dimensional shapes
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  • Learn how to calculate density using mass and volume
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Students in physics or engineering courses, educators teaching buoyancy concepts, and anyone interested in applying mathematical principles to real-world scenarios involving density and floating objects.

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Homework Statement



A solid student in the shape of a rectangular parallelopiped of dimensions 28.0 cm x 19.1 cm x 2.000 m floats horizontally in a calm hot tub filled with warm water; 3.17 cm of the parallelopiped (along the 19.1 cm side) is above the water surface. Find the average density of the student.

Homework Equations



maybe density, volume of parallelopiped

The Attempt at a Solution



I have no idea how to solve this problem. I tried using geometry to find certain things but it did not help. Any help is appreciated! o:)
 
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i have a feeling it has something to do with the buoyancy force. you know anything about that?
 
… eureka … !

jrzygrl said:
I tried using geometry to find certain things but it did not help.

Hi jrzygrl! :smile:

A rectangular parallelepiped (no "o") (also called a cuboid) is just an ordinary rectangular box!

Hint: have you tried thinking about this in the bath, like Archimedes, and then running down the street completely naked, shouting "Eureka!" ? :biggrin:
 

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