Solve Dimensional Analysis: Find Dimensions of B

[Pajamas]

Homework Statement

A=B^3C^1/2 where A has the dimensions L/M and C has dimensions L/T. What are the dimensions of B?

Homework Equations

The Attempt at a Solution

When I worked the problem I got B=M/T but it is wrong. I'm not sure how to approach the question.

 

[Simon Bridge]

You substitute the dimensions into the equation and work out what dimenstions B has to have to make the LHS match the RHS.

Please show your working.

 

[Pajamas]

So far I have B^3=TL/M^2

L/M=B^3(L/T)^1/2
with L/T then in the square root, square both sides and get T/L*L/M^2=B^3, cancel the L on bottom and one on top to get the above answer.

 

[Pajamas]

This doesn't make a lot of sense to me since B is still B^3. Am I supposed to have it look similar to the other side with TLM?

 

[nasu]

So far I have B^3=TL/M^2

L/M=B^3(L/T)^1/2
with L/T then in the square root, square both sides and get T/L*L/M^2=B^3, cancel the L on bottom and one on top to get the above answer.

You have several errors in this.
Squaring will produce B^6. And L^2 in L/M.
Using parentheses will make the things clearer. For you as well as for the people reading your posts.
You don't need to square. Just solve for B and put the dimensions.

 

[Simon Bridge]

T/L*L/M^2=T/L^2/M^2=T/(L^2M^2) ...

Yike... you need to use brackets more to group your terms.
Use square brackets to represent when you mean "dimensions of"[B^3]=(T/L)(L/M^2)=T/(M^2)

OK - but you need ... you've not finished.
(And - check your arithmetic.)