Solve Drowsy Cat Flower Pot Height Question

[rootX]

Homework Statement

A drowsy cat spots a flower pot that sails first up the window, and then down past an open window. The pot is in view for a total of 0.5s, and top to bottom height of the window is 2 m. How high above the window top does the flower pot go?

Homework Equations

Using kinematics equations:
h = v.t + 0.5*a*t^2
v[f]-v = at
or, 2h/t = v[f]+v

The Attempt at a Solution

I assumed that it is going down, while it was viewed.
so, here's my diagram:

0
^|
^|
^s
^|
^|
v
^|
^|
^2 m, 0.5 s
^|
v[f]

(motion is opposite to the direction indicated by the carrot symbols)

so using those equations I get
v = 1.5475 m/s

and as 2as = v^2

so s = 0.122 m

but the answer at the back of the book is 2.34 m ><

 

[rootX]

oops, I got it!
I was not paying enough attention to the wording of this question.
"for a total of 0.5s"

I should have read this thread before posting this one:
https://www.physicsforums.com/showthread.php?t=56362