MHB Solve equation with square roots

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The discussion focuses on solving an equation involving square roots and removing fractions to find possible solutions for x. Participants suggest starting by simplifying square roots and express the need for a step-by-step guide. The equation x^3 + 3x^2 = 4 is confirmed as correct, and participants discuss potential solutions, noting that x = 1 may be a candidate. It is emphasized that solutions should be verified, leading to the conclusion that x = 2 and x = -2 are not valid roots. The conversation highlights the importance of methodical problem-solving in mathematics.
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Can someone show me step by step guide,how to find all possible solutions for example?
 

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andreask said:
Can someone show me step by step guide,how to find all possible solutions for example?
Hi Andreas, and welcome to MHB. You do not say what you have tried in order to tackle this problem. I suggest that you start by looking at those square roots. Can you simplify them at all?
 
Thanks for welcome! I need to remove fractions,and get possible solutions for X. I don't know how to remove fractions,step by step would be very useful.
 
Is the solution x^3+3x^2=4?
 
Hello,
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Regards,
$$|\pi\rangle$$
 
Thanks Petrus, can you continue?
 
Or someone else? Its urgent. Thanks.
 
Hello,
I Will post how to solve it after you post what you think you should do! Tips Dont do the homework in the last minutes

Regards,
$$|\pi\rangle$$
 
Expression skould be without fractions,and then i have to find possible solution(s) for X.
 
  • #10
andreask said:
Is the solution x^3+3x^2=4?
Hello,
My bad did not see this but that is correct! So what is x equal to?

Regards,
$$|\pi\rangle$$
 
  • #11
I think it can be only one! True?
 
  • #12
I want to know how do i get solution in math way. I can see that is 1,but how do i prove it? Can i "disassemble" my last expression? Or if you have time,show me please how would you do it! And many thanks,and sorry for my English!
 
  • #13
Hello,
$$x^2(x+3)=4$$ and you suspect that $$x=1,2,-2$$ BUT you always check if they are correct and Then you see that $$x=2,-2$$ is a fake root!

Regards,
$$|\pi\rangle$$
 
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