Solve Equilibrium Problem: Point A & B Reactions

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SUMMARY

The discussion focuses on solving an equilibrium problem involving two points, A and B, where A is a moving support and B is a fixed support. Participants emphasize the importance of resolving horizontal and vertical forces, as well as moments, to determine the reactions at both points. Key principles include ensuring that the sum of horizontal forces equals zero, the sum of vertical forces equals zero, and that the clockwise moments equal the anti-clockwise moments. Additionally, resolving forces into their x and y components simplifies calculations, particularly when dealing with angled forces.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of force resolution techniques
  • Familiarity with calculating moments
  • Basic trigonometry for resolving forces at angles
NEXT STEPS
  • Study the principles of static equilibrium in mechanics
  • Learn how to resolve forces into components using trigonometric functions
  • Practice calculating moments about various points in a system
  • Explore examples of equilibrium problems involving multiple forces and supports
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Students in engineering mechanics, physics enthusiasts, and anyone involved in structural analysis or statics who seeks to understand equilibrium problems involving multiple forces and supports.

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i am having a problem with this question can someone help me please

Determine the reactions a piont "A" and "B"
please note A is a moving support
and B is a fixed support

look at attached file for the problem

please reply with a full mathematical answer
 

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Please read the various stickys regarding homework help.
 
-Resolve horizontal forces.
-Resolve vertical forces.
-Resolve moments.

Remember that if this is in equilibrium the force acting left and right must be equal.
Forces acting up and down must be equal.
The anti clockwise and clockwise moments at any given point must be equal.

Where exactly are you having difficulty?
 
i don't now how to resolve the moments with the additional horizontal force
 
I can't see your attachement.
 
sumofmoments=0 said:
i don't now how to resolve the moments with the additional horizontal force

Hmm, the link has gone down so I'm sorry i can't be more specific.

If a force is acting upwards or downwards from the point at which you are resolving, it is the horizontal (do not include vertical) distance to the force (so the point to measure to would be exactly above or below the force). multiplied by the force.
Similarly, if a force is acting horizontally from the point at which you are resolving it is the vertical distance multiplied by the force magnitude.

If the force is acting at an angle you can resolve everything into x and y components, to make it much easier to calculate.
For example: For a 10N force acting at 23 degrees, the horizontal force is 10cos23, while the vertical force is 10sin23. From my memory though this doesn't seem to be a problem in your question.

If you're still having trouble and the link is back up i'll try to assist you further.
Have fun.
 

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