Solve Fluid Flow Problem: Find Water Rise in Cylindrical Bucket

[joe007]

Homework Statement

A cylindrical bucket, open at the top, is 30.0 cm high and 14.0 cm in diameter. A circular hole with a cross-sectional area 1.72 cm^2 is cut in the center of the bottom of the bucket. Water flows into the bucket from a tube above it at the rate of 2.00×10^−4 m^3/s ...the question is how high will the water rise??

Homework Equations

A v = A v

q=v/t

The Attempt at a Solution

well so far i know that Av = 2*10^-4

but i am not sure how to approach this problem. do i use Bernoullis principle but how

this is my working out

2*10^-4=1.72*10^-4 *v

v=1.163m/s

help me here cheers

 

[joe007]

oops the question is how high will the water rise??

 

[NascentOxygen]

The rate at which water exits the hole is a function of the height of water in the bucket. The water level will rise until the rate of water running out of the hole exactly equals the rate at which water is being poured into the top. Do you have a relationship for volume/sec exiting a hole related to the water pressure above the hole?

 

[joe007]

yes it is 2*10^-4 m^3/sec