- #1

joe007

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## Homework Statement

A cylindrical bucket, open at the top, is 30.0 cm high and 14.0 cm in diameter. A circular hole with a cross-sectional area 1.72 cm^2 is cut in the center of the bottom of the bucket. Water flows into the bucket from a tube above it at the rate of 2.00×10^−4 m^3/s ...the question is how high will the water rise??

## Homework Equations

A v = A v

q=v/t

## The Attempt at a Solution

well so far i know that Av = 2*10^-4

but i am not sure how to approach this problem. do i use Bernoullis principle but how

this is my working out

2*10^-4=1.72*10^-4 *v

v=1.163m/s

help me here cheers

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