Solve for the moment of this Torque

[andychung0921]

Homework Statement

I have problem on T, is it T is clockwise so the answer is negative?

Relevant Equations

My answer is: M(A)= (Tv x 25)+(Tn x 15)-(300x40)

0=(T sin(5/13)) +(T cos(12/13))- 10200

T=11.27

Please clarify my answer, thank you

 

[berkeman]

Welcome to PF.

Can you please provide the complete problem statement? Is that a 2-bar mass of some sort, welded at the join? It looks like the dimensions are in imperial units (feet, inches), what are the force units in? What are the units in the calculations you have shown?

 

[Lnewqban]

Welcome, Andy!

Why (300x40)?

Intuitively, do you believe that the CCW torque produced by 11.27 can counteract the CW torque produced by 300?

Note that the effective lever of T is about 0.7 the lever of 300.

 

[berkeman]

Intuitively, do you believe that 11.27 can counteract 300?

Well, technically, it depends on the units, eh?