Solve for Theda: sin2theda = 0.339

[mathcrzy]

how do you solve for theda in the equation sin2theda=((2)(9.8))/(7.6^2).

i have figured the right side of the equation to be .339 and so I am left with sin2theda on the left and i don't know how to get theda by itself.

 

[nicksauce]

Take the arcsin of the right side, then divide by 2.

 

[jtbell]

sin2theda

Do you mean $\sin^2 \theta$ (square of the sine of theta) or $\sin (2\theta)$ (sine of (two times theta))?