- #1

Webs993

- 1

- 0

im having a problem solving this problem algebraically please help thanks

e^x - 15e^-x = 2

e^x - 15e^-x = 2

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- Thread starter Webs993
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In summary, solving for x in this equation allows us to find the value of x that satisfies the equation and can be used to find other important information or relationships. This equation can be solved algebraically by factoring and applying basic rules and properties of exponents and logarithms. The first step in solving this equation is to combine like terms by factoring out e^-x. There are restrictions on the possible values of x, as e^x and e^-x can only take on positive values. The significance of the solution(s) is that they represent the value(s) of x that make the equation true and can help us understand the relationship between the two exponential functions and solve related problems.

- #1

Webs993

- 1

- 0

im having a problem solving this problem algebraically please help thanks

e^x - 15e^-x = 2

e^x - 15e^-x = 2

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- #2

praharmitra

- 311

- 1

put e^x = y. And then solve for y

- #3

Mentallic

Homework Helper

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Remember the rule: [tex]a.b^{-c}=\frac{a}{b^c}[/tex]

You will have a quadratic in [tex]e^x[/tex]

You will have a quadratic in [tex]e^x[/tex]

The purpose of solving for x in this equation is to find the value of x that satisfies the equation and makes it true. This value can then be used to find other important information or relationships in the given problem.

Yes, this equation can be solved algebraically by applying basic rules and properties of exponents and logarithms.

The first step in solving this equation is to combine like terms by factoring out e^-x from the left side of the equation. This will result in a quadratic equation in terms of e^x, which can then be solved using the quadratic formula.

Yes, there are restrictions on the possible values of x in this equation. Since e^x and e^-x are both exponential functions, they can only take on positive values. Therefore, any value of x that results in a negative value for either e^x or e^-x is not a solution to the equation.

The solution(s) to this equation represent the value(s) of x that make the equation true. This can be helpful in understanding the relationship between the two exponential functions and can also be used to solve other related problems or equations.

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