Solve for x: e^x - 15e^-x = 2 | Algebraic Solution & Step-by-Step Guide

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The discussion focuses on solving the equation e^x - 15e^-x = 2 algebraically. The user suggests substituting e^x with y, transforming the equation into a quadratic form. This method utilizes the rule a.b^{-c} = a/b^c to simplify the expression, leading to a solvable quadratic equation in terms of y. The solution process is clearly outlined, providing a step-by-step guide to reach the final answer.

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im having a problem solving this problem algebraically please help thanks

e^x - 15e^-x = 2
 
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put e^x = y. And then solve for y
 
Remember the rule: [tex]a.b^{-c}=\frac{a}{b^c}[/tex]

You will have a quadratic in [tex]e^x[/tex]
 

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