(adsbygoogle = window.adsbygoogle || []).push({}); Solve for x-- the inequality of quadratic

1. The problem statement, all variables and given/known data

Solve [tex]\frac{2x}{x^2-9}\le\frac{1}{x+2}[/tex]

3. The attempt at a solution

[tex]x^2-9\not=0[/tex]

.'. [tex]x\in R-\{-3,3\}[/tex]

and

[tex]x+2\not=0[/tex]

.'. [tex]x\in R-\{-2\}[/tex]

then converting the original inequality to

[tex](2x)(x+2)\le(x^2-9)[/tex]

[tex](2x^2+4x)(-x^2+9)\le 0[/tex]

[tex](x^2+4x+9)\le 0[/tex]

As Discriminant <0 it has no real roots

so how to do further...

My assumptions:-

[tex]x^2-9[/tex]should not be zero

[tex]x+2[/tex]should also not be zero

Are my assumptions right?

Any help will be highly appreciated.

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# Homework Help: Solve for x- the inequality of quadratic

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