Solve Free Fall: Time Calculation for Rock Dropped from Tower

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SUMMARY

The discussion focuses on calculating the time it takes for a rock, shot vertically upward with an initial velocity (v0), to fall back down from a height (h) under gravitational acceleration (g). The formula derived is t = (v0 + sqrt((v0)^2 + 2gh))/g. Participants emphasize the importance of understanding kinematic motion equations for constant acceleration to logically derive this formula. They recommend reviewing foundational physics concepts before attempting to apply the formula.

PREREQUISITES
  • Kinematic motion equations for constant acceleration
  • Understanding of gravitational acceleration (g)
  • Basic algebra for manipulating equations
  • Initial velocity concepts in projectile motion
NEXT STEPS
  • Review kinematic motion equations in detail
  • Study gravitational acceleration effects on projectile motion
  • Practice deriving time of flight equations for various initial velocities
  • Explore real-world applications of projectile motion in physics
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of projectile motion and gravitational effects.

Hassin
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I have this excerise to do:

A boy is standing on the tower o height h. He shot with his slingshot a rock vertically up with velocity v0, gravitational acceleration equals g. After what time t the rock has fallen?

Answer is t = (v0 + sqrt((v0)^2 + 2gh))/g
but how to get to it? Computationally and logically - what is the way of thinking step by step? ;)

I would be very grateful for quick answer!
 
Physics news on Phys.org
Please review and understand the kinematic motion equations for constant acceleration. You can find them in the " intro physics formulay" thread at the top of the page, or do a web search. The derivation of these equations should be understood before memorizing and applying them.
 

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