Solve Kinematics in 2D: Rocket Clears 11m Wall

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SUMMARY

The discussion focuses on solving a kinematics problem involving a rocket fired at 75 m/s at a 60-degree angle, aimed at clearing an 11-meter wall located 27 meters away. The key equations utilized include the final velocity equation and the displacement formula, which incorporates gravitational acceleration. The solution requires calculating the rocket's vertical position at the horizontal distance of 27 meters and comparing it to the wall's height to determine the clearance. The approach emphasizes finding the relationship between vertical and horizontal displacements to solve the problem accurately.

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Homework Statement


A rocket is fired at a speed of 75m/s from ground level, at an angle of 60degrees above the horizontal. The rocket is fired toward an 11-m-high wall, which is located 27m away. By how much does the rocket clear the top of the wall?

Homework Equations


final velocity = initial velocity + (acceleration * time)
displacement = (initial velocity * time) + 1/2 * acceleration(gravity) * time(squared)


The Attempt at a Solution


So, I need to find the final position where the rocket will land and the time it takes to do so.
If final velocity = 0 then I think I can go from there. I just don't know if that would be right.
 
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I think you'd need to find how high the rocket is at 27m away. Then if that is bigger than 11m, you would subtract 11 from the value you got.

so you need to find an equation relating vertical displacement (y) and horizontal displacement(x)
 
Got it. Thank you.
 

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