Solve Kinematics Problem: y = y0 + Vot + 1/2gt²

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Homework Help Overview

The discussion revolves around a kinematics problem involving the motion of a ball and a rock, described by the equation y = y0 + Vot + 1/2gt². Participants are exploring the conditions under which the two objects are at the same height.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the timing of the ball's launch relative to the rock and the implications for their respective equations of motion. There is an examination of the signs used in the equations, particularly regarding the direction of velocity and acceleration.

Discussion Status

Some participants have provided insights into the choice of coordinate systems and the assignment of signs to velocity and acceleration. There is an ongoing exploration of the reasoning behind the signs used in the equations, with no clear consensus reached yet.

Contextual Notes

Participants are questioning the assumptions made about the direction of motion and the signs of the terms in the equations, indicating a need for clarification on these concepts.

James_22
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Homework Statement


upload_2016-2-16_19-44-18.png


Homework Equations


y = y0 + volt + 1/2gt²

The Attempt at a Solution


We have to know when yball = y rock
for the ball : t = t-1 because it's throwed 1 sec later the rock.
we have to fine when yball = yrock :

12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²..I find the answer with this equation.. t = 1.45 y=7.43
but my first equation was : -12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²
I put the sign (-) before 12t because I thought when acceleration and velocity have the same direction they have the same sign but when I do that, I don't find the good answer. If someone can explain me that..
Thank you
 
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The signs associated with values depends upon your choice of coordinate system.

Generally you choose your coordinate system before assigning signs to things accordingly. In this case if you chose your coordinates so that upwards is positive, then an upward velocity is positive. Gravitational acceleration is always downwards, so that's why it gets the negative sign.
 
James_22 said:

Homework Statement


View attachment 95959

Homework Equations


y = y0 + volt + 1/2gt²

The Attempt at a Solution


We have to know when yball = y rock
for the ball : t = t-1 because it's throwed 1 sec later the rock.
we have to fine when yball = yrock :

12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²..I find the answer with this equation.. t = 1.45 y=7.43
but my first equation was : -12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²
I put the sign (-) before 12t because I thought when acceleration and velocity have the same direction they have the same sign but when I do that, I don't find the good answer. If someone can explain me that..
Thank you
When you throw something upward, its initial velocity is going to be reduced by the gravitational attraction of the Earth on it, so the velocity term and the acceleration term will have opposite signs. After the object has reached its highest point above the ground and starts to fall back to earth, its velocity is increased by the same gravitational attraction, so the velocity term and the acceleration term will have the same sign.
 
James_22 said:
but my first equation was : -12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²
I put the sign (-) before 12t because I thought when acceleration and velocity have the same direction they have the same sign
Ok, but what made you think they have the same direction here?
 

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