Solve Kirchhoff Problem: Find Voltages of Resistors

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SUMMARY

The discussion focuses on solving a circuit problem using Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL) without employing mesh analysis. The user presents five equations derived from KCL and KVL to find the voltages across resistors but struggles with simplification. Key insights include recognizing that there are only three unique currents in the circuit and the suggestion to combine resistances into equivalent resistances for easier calculations. The teacher emphasizes the necessity of using KCL and KVL separately to achieve consistent results.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Basic circuit analysis techniques
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study how to apply Kirchhoff's Current Law (KCL) in complex circuits
  • Learn to derive equivalent resistances in series and parallel circuits
  • Practice solving circuit problems using Kirchhoff's Voltage Law (KVL)
  • Explore techniques for simplifying circuit analysis without mesh analysis
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of circuit analysis using KCL and KVL.

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Homework Statement


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I am tasked to find the voltage of all the resistors using Kirchhoff Current Law and Voltage Law. TAKE NOTE THAT I AM NOT ALLOWED TO USE MESH ANALYSIS which means I need to assign current for all resistors.

Homework Equations



KCL at node X

-I1 + IT -I3=0

KCL at node Y

-IT + I2 + I4=0

KVL at Left Loop

1I1 - 12 + I2 + 5V = 0

KVL at Right Loop

-2I3 + 6V - 2I4 + 12 = 0

and using both eqns for nodes x and y, I arrived for the fifth equation.

0=I1 - I2 + I3 - I4

The Attempt at a Solution



I arrange all the 5 equations to be easily solved.

0=IT - I1 + 0I2 - I3 + 0I4 + 0
0=IT + 0I1 + I2 + I3 + I4 + 0
0=0IT + I1 + I2 + 0I3 + 0I4 + 5V
0=0IT + 0I1 + 0I2 - 2I3 - 2I4 + 12V
0=0IT + I1 - I2 + I3 - I4

These a lengthy process. Its obvious that I1 = I2 and I3=I4 but the answers I am getting is not the same as these.

Our teacher told us to use these. We are not allowed the short cut which is mesh analysis. What can I do to simplify the solution?
 
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You should be able to use KVL and KCL separately to solve for the circuit values. You don't use them together to solve it. You should get the same answers for each method, however.

Can you show us how to solve the circuit with just one or the other method?
 
Your complicating the problem. There are only three unique currents: (1) through the left branch, (2) through the right branch, and (3) through the middle. Another simplifying procedure is to combine the resistances into a single equivalent resistance in each branch.
 

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