Solve Length Contraction Homework: Find v

Click For Summary

Homework Help Overview

The problem involves length contraction in the context of special relativity, where a spaceship's length is measured differently by an observer at rest and an astronaut in the spaceship. The original poster attempts to find the speed v of the spaceship based on the lengths measured by both observers.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster has attempted to apply the length contraction formula but is uncertain about the correct application of the variables. Some participants suggest expressing the speed as a fraction of the speed of light (v/c) and reformulating the equation accordingly.

Discussion Status

Participants are engaged in exploring the mathematical relationships involved in the problem. Guidance has been offered on how to manipulate the equation to isolate the variable of interest, v/c, but there is no explicit consensus on the final solution yet.

Contextual Notes

The original poster mentions having only one attempt left, indicating a constraint on the number of submissions allowed for the homework problem.

sklotz
Messages
7
Reaction score
0

Homework Statement



A spaceship moves past you at speed v. You measure the ship to be 300 m long, whereas an astronaut on the ship measures a length of 356 m. Find v.

Homework Equations



L=L1sqrt(1-v^2/c^2)

The Attempt at a Solution



I have tried this by using the above formula. I plugged in 300 for L and 356 for L1 and I have tried it the other way as well where I plug in 300 for L1 and 356 for L. The answer is in terms of c. I only have one try left and don't understand what I am doing wrong.
 
Physics news on Phys.org
You are looking for v in terms of c, which means that you are trying to find v/c. So, let x = v/c and write your equation as L = L1sqrt(1-x^2). Show us some of the details of how you would solve this for x.
 
L/L1=sqrt(1-x^2)
(L/L1)^2=1-x^2
1-(L/L1)^2=x^2
x=sqrt(1-(L/L1)^2)
 
Good. That should you get you the correct answer.
 

Similar threads

  • · Replies 36 ·
2
Replies
36
Views
3K
  • · Replies 44 ·
2
Replies
44
Views
2K
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K