Solve Lensmaker Formula for Index of Refraction with Focal Length of 7.3cm

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SUMMARY

The discussion focuses on solving the Lensmaker's Formula to determine the index of refraction for a double concave lens with a focal length of 7.3 cm. The relevant equations include the Lensmaker's Formula, expressed as 1/f = (n-1)(1/R1 - 1/R2), where 'f' is the focal length and 'n' is the index of refraction. The radius of curvature is calculated as double the focal length, resulting in a radius of 14.6 cm. The final conclusion is that the index of refraction is determined to be 2.

PREREQUISITES
  • Understanding of the Lensmaker's Formula
  • Basic knowledge of optics and lens types
  • Ability to manipulate algebraic equations
  • Familiarity with focal lengths and radii in optics
NEXT STEPS
  • Study the derivation of the Lensmaker's Formula in detail
  • Explore the properties of double concave lenses
  • Learn about the impact of different indices of refraction on lens performance
  • Investigate practical applications of the Lensmaker's Formula in optical design
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Students studying optics, physics educators, and anyone involved in optical engineering or lens design will benefit from this discussion.

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Homework Statement


a focal length of 7.3cm for a double concave lens, find the index of refraction using lensmaker law and the radius which can be found using the following equations.


Homework Equations


focal length is 7.3 find radius focal length x 2=radius. Lens maker formula
1/f=(n-1)(1/R1-1/R2)


The Attempt at a Solution



I got 2 for the index of refraction
 
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Looks good to me.
 

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