Solve Log Equations with Log Laws: Examples on Logbase 4, 2, and 10

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Homework Help Overview

The discussion revolves around solving logarithmic equations involving different bases, specifically base 4, base 2, and base 10. The original poster presents several equations and expresses uncertainty in their attempts to manipulate logarithmic expressions correctly.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore various methods for simplifying logarithmic expressions, questioning the correctness of their transformations. There are attempts to clarify the relationship between logarithmic and exponential forms, as well as discussions on how to eliminate logarithms from equations.

Discussion Status

Some participants provide guidance on how to proceed with the equations, suggesting steps to eliminate logarithms and solve for variables. There is an acknowledgment of common mistakes and a light-hearted tone regarding errors made during the problem-solving process.

Contextual Notes

Participants question their understanding of logarithmic properties and the implications of their manipulations. There are references to specific values and hints that may guide the solving process, but no definitive conclusions are reached.

skg94
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Homework Statement



Solve for x

logbase 4 for question 1.

1. log (x+2) - log (x-4) =1/2

log base 2:

2. log (3x+1) = 2 - log (x-1)

log base 10:

3. log sq root (x^2 -21x) =1

similar just different numbers..

log (x-4) - log (x+2) =4 base 2
log (x-4)=4-log(x+2)
log (x^2-2x)^7=21


Homework Equations


Log laws

The Attempt at a Solution



1. log (x+2)/(x-4) = 1/2 - is that right or is it log (x+2) = 1/2 + log (x-4) then cancel the logs. I don't know. When i tried it both didnt work. Maybe i calculated it wrong if its set up right.
2. (3x+1)(x-1) = 2
3x^2-2x-1=2
3x^2-2x-3 - what do i do from here?

3. If you square both sides, or times the square and x by .5 and equal it to zero, i don't know what to do, same process of solving for the later 3 I am pretty sure I am having difficulty with these.

Any help please
 
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1. log (x+2)/(x-4) = 1/2 looks fine. Next step: get rid of the log.

2. (3x+1)(x-1) = 2 -- Here you did just that, i.e. got rid of the log, but only on the left side. You need to fix the right side before you work out (3x+1)(x-1)

3. log( √ something ) = something else ... get rid of the log first:
√ something = 10 ^ (something else) ... square each side:
something = (10 ^ (something else)) ^ 2 = 10 ^ (2 times something else)
This is a quadratic equation which you should be able to solve. (Hint: the number 29 should appear somewhere on the way. If you see that, you're probably getting on okay.)
 
Are you clear on what a logarithm is? It is the inverse to the exponential function- if y= loga(x), then x= ay. So if log4 A= 1/2, then 1/2= 4A. What A makes that true?
 
HallsofIvy said:
So if log4 A= 1/2, then 1/2= 4A. What A makes that true?
Try again.
 
If log4 A = 1/2, then A = 41/2...
 
Oops!:redface:
 
i got them all ha it was just simple as getting rid of the log, silly we all do have our days.. thank to all of you though
 
Mark44 said:
We all have our days ...
Halls seems to have her bad days more often than not!
 
  • #10
oay said:
Halls seems to have her bad days more often than not!
I would disagree on two points:
1. I have rarely seen him make a mistake.
2. Halls is a "he".
 
  • #11
Mark44 said:
I would disagree on two points:
1. I have rarely seen him make a mistake.
2. Halls is a "he".
Ok, I would disagree on just the one point. For some reason, I thought HoI was a she.

But I haven't got enough fingers on both hands to count how many errors he's made in the last month or two! (Ok, maybe that's a bit harsh, but for a "PF MENTOR", far more than enough.)
 

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