Solving Log Equations: 2^x * 4^(x+5) = 4^(2x-1)

  • Thread starter Thread starter Corkery
  • Start date Start date
  • Tags Tags
    Log
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
Corkery
Messages
32
Reaction score
0

Homework Statement


Solve the equation:
2^x multiplied by 4^(x + 5) = 4^(2x - 1)


Homework Equations





The Attempt at a Solution



2^x multiplied by 2^2(x+5)=2^2(2x-1)
x(2x+10)=4x-2
2x^2+10x=4x-2

and that's as far as i could get before I was completely stuck. But this could be completely wrong.
 
Physics news on Phys.org
When you have [tex]2^x2^{2x+10}[/tex], you don't multiply the indexes, you add them.
 
As danago said, [tex]2^x2^{2x+10}= 2^{3x+10}= 2^{4x-2}[/tex]. That gives a simple linear equation for x.


However, IF 2x^2+10x=4x-2 had been correct, that shouldn't give you any problem. It is a quadratic equation and, if you can't factor it, you can use the quadratic formula!
 
Last edited by a moderator: