Samurai Weck
- 11
- 0
Homework Statement
A 1.50-m-long string is under 30.0 N of tension. A pulse travels the length of the string in 50.0 ms.
Homework Equations
v of string = sq rt of (Tension of string/ string's mass-to-length ratio)
string's mass to length ratio= m/L
The Attempt at a Solution
So, the pulse takes 50.0 ms to travel through 1.5 m of string. So, the velocity of the pulse is 1.5 m/.050 s.
V= 1.5/.050 = 30 m/s
Now that I know the velocity, I can use the V of string equation.
V[tex]^{2}[/tex]= T/[tex]\mu[/tex]
[tex]\mu[/tex]= T/V[tex]^{2}[/tex]
[tex]\mu[/tex]= 30.0N/ (30m/s)[tex]^{2}[/tex]
[tex]\mu[/tex]=.033
[tex]\mu[/tex]=m/L
[tex]\mu[/tex]*L=m
.033*1.5=m
m=.049995 or .05 g
However, master physics disagrees with this answer. What am I doing incorrectly?
Last edited: