- #1
CSPhysics
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- 0
Homework Statement
Two equal 1 kg masses are connected by a light 1.6 m string on a flat frictionless surface. A 2 N force is applied to the midpoint of the string which causes the system to accelerate in the positive x-direction.
After 1.5 seconds, the rope makes an angle of 55° with the x-axis.
Determine:
a) The change in the location of the center of mass at time t = 1.5 s
b) The kinetic energy associated with the center of mass motion
c) The work done by the force from time t = 0 to t = 1.5
Homework Equations
W = Fd
Δp = mΔv = Ft
K = 0.5mv2
The Attempt at a Solution
I started with part b and solved for the center of mass velocity.
Ft = mv
v(t) = Ft/m
v(1.5) = (2)(1.5)/2 = 1.5 m/s
K = 2.25 JThen for part a, I integrated my velocity function to get
x(t) = Ft2/2m
x(1.5) = 1.125
For part c, I calculated force displacement to get work
force displacement = 1.125 + 0.8sin(55) = 1.78 m
W = Fd
W = 2 * 1.78
W = 3.56 J
I have no idea if what I did is correct, and I haven't been able to find any similar questions online. Any help is appreciated!