# Solve Mass & Volume of CO2 & O2: 6CO2 + 6H2O -> C6H12O6

• Kreme
In summary, the given balanced chemical reaction is 6CO2 + 6H2O -> C6H12O6 + 6O2 and the question asks for the mass of CO2 reacted and the volume of O2 gas formed if 3.0 mols of H2O react completely. The solution involves using the molar ratio provided by the reaction to calculate the amount in moles of CO2 and O2, and converting the moles of CO2 to grams using its molar mass. However, to determine the volume of O2 gas formed, more information such as concentration or pressure is needed.
Kreme

## Homework Statement

6CO2 + 6H2O -> C6H12O6 + 6O2 If 3.0 mols H2O react completely...

## Homework Equations

A) What mass of CO2 is reacted?
B) What volume of O2 gas is formed?

## The Attempt at a Solution

No idea, hoping someone would help me?

This is a pretty strightforward problem.
Since you have your balanced chemical reaction you have your molar ratio.
That is what is always going to get you from one amount of a certain substance to the amount of the other.
therefore, since it is a molar ratio, you need to find the amount in moles of a given substance thati s reacting.
Lucky for you, you knwo already that 3 moles of water are reacting.
using the molar ratio provided by the reaction, you can get both the amount in moles of CO2 and O2. Using your molar mass of CO2 you can get grams.
How ever for the volume of O2 gas I am pretty sure oyu need more information... like a concentration or a pressure. For instance, a greater volume of O2 will be produced in the same reaction at a higher temperature.

I would suggest starting by using the balanced chemical equation to determine the molar ratios between the reactants and products. From this, you can calculate the number of moles of CO2 and O2 produced based on the given 3.0 moles of H2O. Then, using the molar mass of CO2 and the ideal gas law, you can calculate the mass of CO2 and the volume of O2 gas produced. It is important to note that the ideal gas law may not be applicable in all situations, so further information about the conditions of the reaction may be needed for a more accurate calculation.

## 1. How do you calculate the mass of CO2 and O2 in the given equation?

In order to calculate the mass of CO2 and O2, we first need to determine the molar mass of each element. The molar mass of carbon is 12.01 g/mol, oxygen is 16.00 g/mol, and hydrogen is 1.008 g/mol. Using the coefficients in the equation, we can determine that there are 6 moles of both CO2 and O2. Therefore, the mass of CO2 would be 6 x 12.01 = 72.06 g and the mass of O2 would be 6 x 16.00 = 96.00 g.

## 2. How is the volume of CO2 and O2 related to their mass?

The volume of a gas is directly proportional to its mass and inversely proportional to its density. Therefore, as the mass of CO2 and O2 increases, so does their volume.

## 3. What is the significance of the given equation in terms of photosynthesis?

The equation represents the process of photosynthesis, where carbon dioxide and water are converted into glucose, a form of stored energy, through the use of sunlight. This process is essential for the survival of plants and other autotrophs, as it provides them with the necessary energy to carry out their cellular functions.

## 4. Can this equation be balanced using any other coefficients?

No, this equation is already balanced as it follows the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction. The same number of atoms of each element must be present on both sides of the equation.

## 5. How does the molar mass of CO2 and O2 affect the overall mass of the products in the equation?

The molar mass of CO2 and O2 contribute to the overall mass of the products in the equation, as they are the main components of the resulting glucose molecule. Without these elements, the glucose molecule would not be formed and the overall mass of the products would be significantly lower.

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