Solve Mechanics Homework: Driving Force & Tow Bar Tension

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In summary, a car weighing 1000kg is towing a caravan weighing 600kg up a road with a 1m vertical rise for every 20m of length. The combination is experiencing frictional resistant forces of 200N and 100N, respectively. With the engine exerting a constant driving force, the combination has an acceleration of 1.2 m/s^2. To find the driving force, the combined mass of 1600kg was multiplied by the acceleration. However, a more thorough approach is needed by drawing a free body diagram and considering all forces acting on the system, including friction and gravity components.
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Doubell
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Homework Statement



a car of 1000kg tows a caravan of mass 600kg up a road which rises 1 m vertically for every
20 m of its lenght. there are constant frictional resistant forces of 200 N and 100 N to the motion of the car and the motion of the caravan respectively. the combination has an acceleration of 1.2 m/s^2 with the engine exerting a constant driving force. find (a) the driving force, (b) the tension in the tow bar. (g= 10 m/s^2)



Homework Equations



F=m*a

The Attempt at a Solution



using F=m*a i multiplied the combined mass (1600kg) * 1.2 m/s^2 and got 1920 N i don't think that is right the method seems to be too easy plus i know that something about the rising of the road by 1m for every 20m of its length should be used to calculate the driving force as for the tension i don't know how to start it
 
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  • #2


Remember it is not F=ma, it's F_net =ma. That means the net force up the plane is 1920N. You need to draw a free body diagram of the car-caravan system to find all the forces acting on the system. Along (parallel to) the incline, the driving force is just one of those forces. What are the others , and in what direction to they act? The algebraic sum of those forces is the NET force acting up the incline. (Hint: there are also friction and components of the gravity forces acting along the incline).
 

FAQ: Solve Mechanics Homework: Driving Force & Tow Bar Tension

1. What is the driving force in mechanics homework?

The driving force in mechanics homework refers to the force that causes an object to move or accelerate. It can be calculated using the formula F=ma, where F is the force, m is the mass of the object, and a is the acceleration.

2. How is the driving force related to the tow bar tension?

The driving force is directly related to the tow bar tension. The tow bar tension is the force applied by the tow bar to the object being towed, and this force is what causes the object to move or accelerate. The greater the tow bar tension, the greater the driving force and the faster the object will move.

3. What factors affect the driving force and tow bar tension?

The driving force and tow bar tension can be affected by a variety of factors, including the mass of the object being towed, the angle and position of the tow bar, and any external forces acting on the object.

4. How do we calculate the tow bar tension in mechanics homework?

The tow bar tension can be calculated using the formula T=mg(sinθ+μcosθ), where T is the tow bar tension, m is the mass of the object, g is the acceleration due to gravity, θ is the angle of the tow bar, and μ is the coefficient of friction between the object and the surface it is being towed on.

5. Can the driving force and tow bar tension be greater than the weight of the object being towed?

Yes, the driving force and tow bar tension can be greater than the weight of the object being towed. This is because the driving force and tow bar tension are determined by not only the weight of the object, but also the other factors mentioned in question 3. As long as these factors are greater than the weight, the driving force and tow bar tension can be greater as well.

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