1. The problem statement, all variables and given/known data A tow truck driver hooks up a car to tow it up the hill. The car weighs 1500kg. the cable makes an angle of28 degrees with ground. the cables tension is 1900 N . the static coefficitient is 0.5 and the acceleration is at 6/m s^2 . what is the frictional force on the car 2. Relevant equations ƩF=ma 3. The attempt at a solution using my diagram and summing the forces in the xdirection i get ƩF= Tension + Fgravity- Force of Friction= ma 1900sin28-9.8sin28-0.5N=1900 X 6 ...then I solve for N?