Solve Min-Max Problem: Find Optimal Price of Single Call

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SUMMARY

The optimal price for a single phone call to maximize income is 0.75. The income function is defined as f(x) = (0.5 + 0.05 * x)(200 - 10x), where x represents the number of 5-cent increments. For each increment of 5 cents, the average number of calls decreases by 10. The solution involves building this function and finding its derivative to determine the maximum income point.

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Yankel
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Hello, I need some help with this simple question, don't know why I got it wrong...

The price of a single phone call is 0.5\$ and the average number of calls made in a month is 200.

For each 5 cent of price increment, the average number of calls made by the customers decreases by 10.

Find what should be the cost of a single call so that the income will be maximal.

I know I need to build up a function and then find derivative and all that, I just can't build the right function...
The final answer is by the way 0.75\$.

Thank you
 
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Yankel said:
Hello, I need some help with this simple question, don't know why I got it wrong...

The price of a single phone call is 0.5 USD and the average number of calls made in a month is 200.

For each 5 cent of price increment, the average number of calls made by the customers decreases by 10.

Find what should be the cost of a single call so that the income will be maximal.

I know I need to build up a function and then find derivative and all that, I just can't build the right function...
The final answer is by the way 0.75$.

Thank you

1. Please don't use the dollar sign.

2. Let x be the number of 5-cts-increment. Then the income is determined by:

$ \displaystyle{f(x)=(0.5 + 0.05 \cdot x)(200-10x)} $

3. Go ahead!
 

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