Solve Molarity for 40 g Sodium Hydroxide in 1 L Solution

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SUMMARY

The molarity of a solution containing 40 grams of sodium hydroxide (NaOH) dissolved in 1 liter of water is calculated to be 1 M. This is derived from the formula for molarity, which is the number of moles of solute divided by the volume of solution in liters. The calculation shows that 40 grams of NaOH corresponds to 1 mole, leading to a molarity of 1 M. However, there is confusion regarding a reference to 10 grams in the textbook, which is incorrect based on the provided data.

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Homework Statement


another satII chem question:
Forty grams of sodium hydroxide is dissolved in enough water to make 1 liter of solution. What is the molarity of the solution?
(A) 0.25 M
(B) 0.5 M
(C) 1 M
(D) 1.5 M
(E) 4 M

Homework Equations



Molarity = (number of moles of solute) / (1 L of solution)

The Attempt at a Solution


well, i converted 40 g of NaOH to moles so...
40 g NaOH x (1 mol NaOH) / (40 g NaOH)= 1 mol
so...
Molarity = (1 mol) / (1 L) = 1 M

but the book says the answer is (A) & their explanation is...
NaOH is 40 g/mol. 10 g is 10/40 or 0.25 mol in 1 L or 0.25 M

i have no idea, how they're getting the 10.
and would appreciate any help at alll.

thank you so much guys :biggrin:

also; if anyone knows how to insert division signs to make the presentation look ANY better, because right now it looks messy!...i was trying to use the underline thing, but the formatting got all messed up!
 
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40 gr in 1 liter gives 1 mol NaOH solution, I think the book is wrong because I can't see any reason for using 10 gr that is not given in the question.
 
thanksyou :)

YAY!
thank you so much guys!
i was feeling a little down, as to why i wasn't getting this little molarity problem.
and two physics-forum people agreeing with me makes me feel a whole lot better.
thanks once again! :biggrin:
 
Do you think it is possible that someone penciled in the '4' in 40 from what was originally a '1'? If so, that's a pretty dirty trick.
 

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