Solve Molarity for 40 g Sodium Hydroxide in 1 L Solution

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Discussion Overview

The discussion revolves around calculating the molarity of a sodium hydroxide solution, specifically addressing a homework problem that presents conflicting answers regarding the correct molarity based on the given mass of solute and volume of solution.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant calculates the molarity as 1 M by converting 40 g of NaOH to moles, asserting that 40 g corresponds to 1 mol in 1 L of solution.
  • Another participant expresses confusion about the book's answer of 0.25 M, noting that they do not understand the reference to 10 g in the explanation provided.
  • A third participant agrees with the initial calculation of 1 M and questions the validity of the book's answer, stating that there is no basis for using 10 g as mentioned in the book.
  • One participant suggests that the discrepancy might stem from a possible error in the problem's text, speculating that a number may have been altered from '1' to '4'.

Areas of Agreement / Disagreement

Participants generally disagree on the correct molarity of the solution, with some supporting the calculation of 1 M and others questioning the book's answer of 0.25 M. The discussion remains unresolved regarding which answer is correct.

Contextual Notes

The discussion highlights a potential misunderstanding or error in the problem statement, particularly concerning the reference to 10 g, which is not explicitly stated in the original question.

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Homework Statement


another satII chem question:
Forty grams of sodium hydroxide is dissolved in enough water to make 1 liter of solution. What is the molarity of the solution?
(A) 0.25 M
(B) 0.5 M
(C) 1 M
(D) 1.5 M
(E) 4 M

Homework Equations



Molarity = (number of moles of solute) / (1 L of solution)

The Attempt at a Solution


well, i converted 40 g of NaOH to moles so...
40 g NaOH x (1 mol NaOH) / (40 g NaOH)= 1 mol
so...
Molarity = (1 mol) / (1 L) = 1 M

but the book says the answer is (A) & their explanation is...
NaOH is 40 g/mol. 10 g is 10/40 or 0.25 mol in 1 L or 0.25 M

i have no idea, how they're getting the 10.
and would appreciate any help at alll.

thank you so much guys :biggrin:

also; if anyone knows how to insert division signs to make the presentation look ANY better, because right now it looks messy!...i was trying to use the underline thing, but the formatting got all messed up!
 
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40 gr in 1 liter gives 1 mol NaOH solution, I think the book is wrong because I can't see any reason for using 10 gr that is not given in the question.
 
thanksyou :)

YAY!
thank you so much guys!
i was feeling a little down, as to why i wasn't getting this little molarity problem.
and two physics-forum people agreeing with me makes me feel a whole lot better.
thanks once again! :biggrin:
 
Do you think it is possible that someone penciled in the '4' in 40 from what was originally a '1'? If so, that's a pretty dirty trick.
 

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