- #1

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I am trying to solve the following equation analytically. I think the solution shouldnt be that hard but I'm really rusty on these kind of things.

V' - k*V^-1/2 = 0

where k is constant. Any help is appreciated, got to turn this in tomorrow!

- Thread starter pd1zz13
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- #1

- 3

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I am trying to solve the following equation analytically. I think the solution shouldnt be that hard but I'm really rusty on these kind of things.

V' - k*V^-1/2 = 0

where k is constant. Any help is appreciated, got to turn this in tomorrow!

- #2

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Try separation of variables.

- #3

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V'' - k*V^-1/2 = 0

I then said u = V' therefore u' = u(du/dV)

so the new equation is :

u(du/dV) = V^-1/2*k

Im a little rusty on separation of variables but I got a u in the final answer which means I have to integrate again since I need the final answer in terms of V.

The goal is to prove k is proportional to V^3/2

Am i doing this right?

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