Solve Olimpiad Problem: Draw u(5,x) Graph

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Discussion Overview

The discussion revolves around solving an Olympiad problem involving a partial differential equation of the form u_{tt} = a(x)*u_{xx}, where the coefficient a(x) varies based on the value of x. Participants are focused on finding the graph of the function u(t, x) specifically at t = 5, with initial conditions provided.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses difficulty with the problem and requests hints for solving it.
  • Another participant suggests that generalized functions may be necessary for the solution, though they are not entirely certain.
  • A question is raised regarding the notation u_{tt}, with clarification sought on whether it represents a double time derivative.
  • There is a confirmation that the indices should be positioned at the bottom, indicating a notation issue.
  • A participant mentions they can solve the problem for specific intervals but struggles to find a general solution applicable across all intervals.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the approach to solving the problem, with multiple viewpoints on the necessary methods and notation. The discussion remains unresolved regarding the general solution.

Contextual Notes

There are limitations in the discussion related to the assumptions about the solution method, the dependence on the definitions of generalized functions, and the lack of clarity on how to transition between different intervals in the solution.

Mechmathian
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I am having problems on this "said to be easy" olimpiad problem.
If anyone can give me some hints, I'd be greatful!
(unfortunately I could not get the subscripts to work, that is why everything that is superscribed should be lowered)
u[tex]_{tt}[/tex] = a(x)*u[tex]_{xx}[/tex]. x[tex]\in R[/tex]

a(x) = 1 (if x>0)
a(x) = 2 (if x<=0)

u|[tex]_{t=0}[/tex] = b(x) u[tex]_{t}[/tex]|[tex]_{t = 0}[/tex] = 0

b(x)= 0 when x[tex]\notin[/tex] [0, 1]
b(x) = 2x-2 when x[tex]\in [1, 1.5][/tex]
b(x) = -2x+4 when x[tex]\in[1.5, 2][/tex]

The problem is to draw the graph of the function u(t, x) when t = 5.
 
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I think that generalized functions have to be used here, although I am not 100% sure..
 
Whats U^tt. Is that supposed to be a double time derivative?
 
yes, the indexes need to be a the bottom
 
The thing is that I can solve the problem for any of the intervals ((-inf, 1), (1, 1.5), (1.5, inf)). But don't know how to get the general solution
 

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