# Solve Physics Equation - 6*10^-9 = 2pi*√(m/80)

• amoateng
In summary, to isolate m in the equation 6,0 * 10^-9 = 2pi*√(m/80), you can follow these steps: 1. Divide both sides by 2pi: 6*10^-9 = √(m/80) 2. Square both sides: (6*10^-9)^2 = m/80 3. Multiply both sides by 80: m = 80*(6*10^-9)^2 4. Simplify: m = 80*[(6*10^-9)^2]/(4pi^2) 5. Use a calculator to get the final
amoateng

6,0 * 10^-9 = 2pi*√(m/80)

i thought it would be something llike :
6*10^-9 = 2pi*√(m/80)
(6*10^-9)/(2pi) = √(m/80)
[(6*10^-9)^2]/(4pi^2)= m/80
m = 80*[(6*10^-9)^2]/(4pi^2) but the answer on the answer sheet is: 7.3*10^-17

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I moved this to the Homework section. And omoateng, you need to show some work in order to get our help. We are not an answer engine that you type questions into.

What steps should you take to isolate m in the equation?

EDIT -- the OP added some work to his first post...I'll try to answer below.

Last edited:
Just type your final line into your calculator again. I get that correct answer with my calculator and your final line. If you aren't using an RPN calculator, be careful how you handle the intermediate results. You did the algebra correctly.

I get

$$m = \frac{72}{\pi^2} .10^{-17}$$

which pretty much equals 7.3x10^-17, as far as I can tell.

edit: note, this is equal to your answer for m (just expressed differently)

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## What is the equation "6*10^-9 = 2pi*√(m/80)" used for?

The equation "6*10^-9 = 2pi*√(m/80)" is used to solve for the mass (m) of an object when given a known period (6*10^-9 seconds) and the length of the pendulum (80 cm). It is commonly used in pendulum experiments and calculations in physics.

## What are the units for each variable in the equation "6*10^-9 = 2pi*√(m/80)"?

The units for the period (6*10^-9 seconds) are in seconds, while the units for the length of the pendulum (80 cm) are in centimeters. The mass (m) is typically measured in kilograms for this equation to work.

## What does the number 2pi represent in the equation "6*10^-9 = 2pi*√(m/80)"?

The number 2pi (2π) represents the ratio of a circle's circumference to its diameter. In this equation, it is used to convert the period (in seconds) to the frequency of oscillation (in hertz) of the pendulum.

## How do I solve for the mass (m) in the equation "6*10^-9 = 2pi*√(m/80)"?

To solve for the mass (m), you will need to isolate it on one side of the equation. First, square both sides of the equation to get rid of the square root. Then, divide both sides by 2π to get m/80 by itself. Finally, multiply both sides by 80 to get the final answer for the mass (m).

## What factors can affect the accuracy of the solution to the equation "6*10^-9 = 2pi*√(m/80)"?

The accuracy of the solution to this equation can be affected by various factors, such as experimental errors, environmental factors (e.g. air resistance), and the precision of the measurements for the period and length of the pendulum. Additionally, the equation assumes a perfectly ideal pendulum with no external forces acting on it, which may not be the case in real-world scenarios.

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