Solve polynomial using complex number

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To solve the polynomial equation w^3 = 1 using de Moivre's theorem, the roots are found as complex numbers. For the second equation (z + i)^3 + (z - i)^3 = 0, it can be transformed by dividing both sides by (z + i)^3, leading to the equation (i - z)/(i + z) = 1. This form allows the application of the results from the first equation. The key is recognizing that -1 can be expressed as (-1)^3, which connects both problems. Understanding this relationship enables the solution of question (b) using the results from question (a).
songoku
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Homework Statement
a. Solve w^3 = 1 in de moivre form

b. You must use result from (a) to solve (z + i)^3 + (z - i)^3 = 0
Relevant Equations
de moivre
I can do question (a). For question (b), I can not see the relation to question (a). Can we really do question (b) using result from (a)? Please give me little hint to relate them

Thanks
 
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songoku said:
Homework Statement: a. Solve w^3 = 1 in de moivre form

b. You must use result from (a) to solve (z + i)^3 + (z - i)^3 = 0
Homework Equations: de moivre

I can do question (a). For question (b), I can not see the relation to question (a). Can we really do question (b) using result from (a)? Please give me little hint to relate them

Thanks

Divide both sides in (b) by ##(z+i)^3## and use that ##-1=(-1)^3## to write the equation in the form

$$\left(\frac{i-z}{i+z}\right)^3=1$$

Then you can use (a) to proceed.
 
Math_QED said:
Divide both sides in (b) by ##(z+i)^3## and use that ##-1=(-1)^3## to write the equation in the form

$$\left(\frac{i-z}{i+z}\right)^3=1$$

Then you can use (a) to proceed.

Thank you very much
 

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