Solve Polyprotic pH Problem: K2HPO4 & H3PO4 (65 Chars)

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SUMMARY

The discussion focuses on calculating the volume of 1 M H3PO4 required to adjust the pH of a 0.05 M K2HPO4 solution in 800 mL of water to 7.0. The mass balance equation for H3PO4 and the charge balance equation for K2HPO4 are established as foundational steps. At pH 7.0, the presence of H3PO4 and PO43- can be ignored, allowing the use of the Henderson-Hasselbalch equation and stoichiometry to simplify the problem-solving process. Participants emphasize the importance of charge and mass balance in polyprotic acid-base calculations.

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A .05 M sample of K2HPO4 was dissolved in 800 mL of water, and the pH was adjusted to 7 by using a 1 M solution of H3PO4 followed by water bringing the volume up to 1 L. How many mL of H3PO4 were added? (On this problem charge and mass balance have to be used.)

My problem is just in the very beginning, as my book is terrible, I am not entirely sure on how to approach this problem.

Im assuming the mass balance for H3PO4 will be:

[H3PO4] + [H2PO4- ] + [HPO42-] + [PO43-] = 1 M

And the charge balance for K2HPO4 would be:

[H+] + [K+] = [OH-] + [H2PO4-] + 2*[HPO42-] + 3*[PO43-]


I'm really uncertain whether I'm missing anything or what the next step should be.
 
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Please try these lectures on pH calcualtion as a starting point.

At pH 7.0 you can ignore presence of H3PO4 and PO43-. I have a gut feeling that this question can be solved just using Henderson-Hasselbalch equation and stoichiometry.

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