Solve Q(√7,√5) and Prove φ(4√3) = ± 4√3 | Galois Theory Help

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The discussion focuses on solving the field extension Q(√7, √5) and proving that φ(4√3) = ± 4√3 within the context of Galois Theory. Participants are tasked with identifying the polynomial f(x) such that Q(√7, √5) is isomorphic to Q[x]/(f(x)). Additionally, they must demonstrate the properties of the Galois group Gal(Q(4√3)|Q) to validate the equation involving φ. The conversation highlights the importance of understanding field extensions and Galois groups in advanced algebra.

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I am so confused with these two questions. Can anyone help me out?

1) Please find [Q((√7 , √5) : Q] by finding f(x) such that Q (√7 , √5) ≅ Q[x]/(f(x)),

2) Prove that φ(4root√3) = ± 4root√3, Given that φ ∈ Gal(Q(4root√3)|Q)
 
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