Solve Quadratic Equations with Alpha1 x Beta1 and Alpha2 x Beta2"

[kasot.tope]

express the following in terms of alpha1 x beta1 and alpha2 x beta2

alpha1 x alpha 2=beta1 x beta2

 

[HallsofIvy]

$\alpha_1\alpha_2= \beta_1\beta_2$ gives
$$\frac{\alpha_1}{\beta_1}= \frac{\beta_2}{\alpha_2}$$

or $\alpha_1\beta_1^{-1}= \alpha_2^{-1}\beta_2$

but there is no way to express it in terms of the products $\alpha_1\beta_1$ and $\alpha_2\beta_2$.

 

[Mentallic]

Well you can still find out what $\alpha_1\beta_1$ is equal to in terms of the 4 variables.

start with $\alpha_1\alpha_2=\beta_1\beta_2$ and multiply both sides by $\beta_1$

 

[The Chaz]

Well you can still find out what $\alpha_1\beta_1$ is equal to in terms of the 4 variables.

start with $\alpha_1\alpha_2=\beta_1\beta_2$ and multiply both sides by $\beta_1$

That's like using a word in its own definition, but yes, it can be done.

 

[Mentallic]

Either that or we have to break it to the OP that we can't define that word

 

[kasot.tope]

hmmm... i still need some one to help me with it

 

[The Chaz]

kasot.
There must be more to this problem. You are asking us to express an equality "in terms of" parts of that equality. It can be done, but we might be more helpful with more information.
1) where is this from?
2) is English your native language?
3) what course/class is this for?

 

[kasot.tope]

kasot.
There must be more to this problem. You are asking us to express an equality "in terms of" parts of that equality. It can be done, but we might be more helpful with more information.
1) where is this from?
2) is English your native language?
3) what course/class is this for?

1) it is a question i saw in a test book am studying and it is not my course work
2) NO, BUT IT IS MY OFFICIAL LANGUAGE
3) it for general maths

 

[Mentallic]

Then my response would be your best bet at getting an answer.